Product identification description

Matters needing attention

1.Filtration:the recommended filtration precision for normal industrial application is 25 um, andallowable precision is 75 um under low-pressure low-speed or interval working conditions.

2.Viscosity: The optimum performance could only be obtained in the good viscosity condition andtherefore in most conditions, the viscosity of the motor should be within the range of 15-1000 cst.

3.Before the first time start-up, the hydraulic motor must be filled with hydraulic oil to prevent damage.4.Leakage:The drain port should be separately connected to the tank.Oil drain pipe should beinstalled below the oil level surface of the tank.Normally,the allowable maximum pressure for the motorbody is o.1 Mpa.

5.The highest horizontal level of the drain pipe should be higher than the highest horizontal position ofthe motor housing to prevent the emptying oil storage.

6.The hydraulic motor can be installed in any position with rigid support. During the installation,ensurethat the drive shaft of the hydraulic motor and the output shaft of the hydraulic motor are concentric.7.Strictly ensure the cleanliness of the oil port connection, and keep away any solid particles.

8.Release both the radial and axial loads of the output shaft to enable the longer life of the motor.

9.The type of motor cannot work as a pump.

10.As the F series motors adopt a hydrostatically-balanced structure toincrease the leakage of the motor, ensure the inner diameter of thedrain pipe must not be less than 12 mm when it is connected with theexternal drain pipe, otherwise,the oil seal could be impacted ordamaged.When connecting the tie-in of the drain port, do notover-screw in to avoid damage of the parts.

Computational formula

①    The actual output torque of the hydraulic motor：M=0.159（P1-P2）V·ηm（N.m）

Where：P1、P2------------------------- Inlet and outlet pressure（MPa）

V--------------------------------- Displacement（ml/r）

ηm------------------------------- Mechanical efficiency（%）

②    Output power of the hydraulic motor：

N=（M·n）/9950（kW）N=[q（P1-P2）/60000]·ηm·ηv（kW）

Where：n-------------------------------- Rotation speed（r/min）

q-------------------------------- Input flow（ml/min）

ηv-------------------------------- Volumetric efficiency（%）

③    Rotating speed of the hydraulic motor：

n=q/V·ηv（r/min）